3[x+2]+2x=7[x-1]+9

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Solution for 3[x+2]+2x=7[x-1]+9 equation:


Simplifying
3[x + 2] + 2x = 7[x + -1] + 9

Reorder the terms:
3[2 + x] + 2x = 7[x + -1] + 9
[2 * 3 + x * 3] + 2x = 7[x + -1] + 9
[6 + 3x] + 2x = 7[x + -1] + 9

Combine like terms: 3x + 2x = 5x
6 + 5x = 7[x + -1] + 9

Reorder the terms:
6 + 5x = 7[-1 + x] + 9
6 + 5x = [-1 * 7 + x * 7] + 9
6 + 5x = [-7 + 7x] + 9

Reorder the terms:
6 + 5x = -7 + 9 + 7x

Combine like terms: -7 + 9 = 2
6 + 5x = 2 + 7x

Solving
6 + 5x = 2 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
6 + 5x + -7x = 2 + 7x + -7x

Combine like terms: 5x + -7x = -2x
6 + -2x = 2 + 7x + -7x

Combine like terms: 7x + -7x = 0
6 + -2x = 2 + 0
6 + -2x = 2

Add '-6' to each side of the equation.
6 + -6 + -2x = 2 + -6

Combine like terms: 6 + -6 = 0
0 + -2x = 2 + -6
-2x = 2 + -6

Combine like terms: 2 + -6 = -4
-2x = -4

Divide each side by '-2'.
x = 2

Simplifying
x = 2

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